2x/x^2+36=0

Solution for 2x/x^2+36=0 equation:

2x/x^2+36=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


2x+36*x^2=0

We add all the numbers together, and all the variables

36x^2+2x=0

a = 36; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·36·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*36}=\frac{-4}{72}
=-1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*36}=\frac{0}{72}
=0
$